Question:
Restating answer 5 3/32
Answer:
1), 4 aces, one 5 of hearts and one 3 of spades, a total of 6 out of 52 cards, P(ace OR 5 of hearts OR 3 of spades) = 6/52 The question seems to be the three separate probabilities, though.
Then the answers would be 4/52. 1/52 and 1/52
2) Correct again, 200-12 = 188 non defective bulbs out of 200
3) 13 hearts in your 52 card deck, correct again.
4) 4 possible outcomes, HH, HT, TH, TT, two of those have one head, correct again.
5) The chance to get one head followed by 4 tails: 1/32 (1/2 for the first tails, 1/2 for each subsequent heads = 1/2^5 = 1/32)
You have 4 more ways of getting 4 tails (heads on second toss, third toss, fourth toss and final toss) total: 5/32. correct again.
6) 36 possible outcomes when tossing two dice.These give you a sum of 7: 1-6, 2-5, 3-4, 4-3, 5-2, 6-1 That's 6 favorable outcomes out of 36, probability = 6/36 = 1/6
5 correct answers out of 6: good job!
Category: Science